提交时间:2020-08-22 14:34:09

运行 ID: 6079

#include <iostream> using namespace std; int main() { double t, m, p, d; p = 150*0.4463; d = 250*0.4663; cin >> t ; if (t<=150) { m= t*0.4463; printf ("%.1f\n" , m); } else if (t>=150 && t <= 400) { m= (t*0.4663)+ p; printf ("%.1f\n" , m); } else if (t<400) { m= (t*0.5663)+ p + d; printf ("%.1f\n" , m); } return 0; }