提交时间:2021-07-10 20:13:33

运行 ID: 14209

#include <iostream> #include <cstring> using namespace std; int main() { long n,len; char l[65]; cin>>n; for(int i=0; i<n; i++) { cin>>(l); len=strlen(l); if(l[len-1] % 2==0) cout<<"even"<<endl; else cout<<"odd"<<endl; } return 0; }