提交时间:2021-07-10 19:48:23

运行 ID: 14199

#include <iostream> using namespace std; int main() { int n,l[100000]; cin>>n; for(int i=0; i<n; i++) { cin>>l[i]; } for(int i=0; i<n-1; i++) { if(l[i]%2==0) cout<<"even"<<endl; else cout<<"odd"<<endl; } if(l[n-1]%2==0) cout<<"even"; else cout<<"odd"; return 0; }