提交时间:2021-07-10 18:19:13

运行 ID: 14120

#include <iostream> using namespace std; int main () { int n; char j[101]; cin>>n>>j; for (int i=0; i<=n; i++) { if (j[i]%2==0) { cout << "even" << endl; } else { cout << "odd" << endl; } } return 0; }